Blackwarrior
Member
Im on a learning curve now whilst i wait for parts and i would like to know how one knows that a specific head speed will create lift.
i know from members in a previous thread that:-
Head Speed = Motor KV * Battery voltage * Efficiency * (Pinion Teeth count / Main gear Teeth count) this is at 100% throttle
my Blade heli that destroyed itself was due to excessive head speed, this is my setup.
Motor is 4200KV, 14T pinion, 140T main gear. (3S battery was fully charged)
HS = 4200 * 12.6 * 0.9 * (14/140) = 4762 RPM at 100% throttle, mine was set to 70% MAX in normal mode, therefore HS = 4762 * 0.7 = 3333 RPM
OK, this is great, BUT how do we know what head speed will give us lift, there must obviously be other formulae that have parameters such as rotor blade lift characteristics, weight of Helicopter etc etc, the Mathematics behind this must be phenomenal..
thanks
i know from members in a previous thread that:-
Head Speed = Motor KV * Battery voltage * Efficiency * (Pinion Teeth count / Main gear Teeth count) this is at 100% throttle
my Blade heli that destroyed itself was due to excessive head speed, this is my setup.
Motor is 4200KV, 14T pinion, 140T main gear. (3S battery was fully charged)
HS = 4200 * 12.6 * 0.9 * (14/140) = 4762 RPM at 100% throttle, mine was set to 70% MAX in normal mode, therefore HS = 4762 * 0.7 = 3333 RPM
OK, this is great, BUT how do we know what head speed will give us lift, there must obviously be other formulae that have parameters such as rotor blade lift characteristics, weight of Helicopter etc etc, the Mathematics behind this must be phenomenal..
thanks